How to convert arcsec to steradians

  • Thread starter Thread starter Teenion
  • Start date Start date
  • Tags Tags
    Convert
AI Thread Summary
To convert the angular size of a spherical object from arcseconds to steradians, one must consider the subtended angle and the distance from the observer. The relationship involves dividing the visible area by the square of the distance (R²) to obtain the size in steradians. Simply squaring the angular size in arcseconds does not yield a valid conversion, as arcseconds represent an angle while steradians represent a solid angle. Understanding the object's shape is crucial for accurate calculations. Therefore, the conversion requires specific geometric considerations rather than a direct mathematical transformation.
Teenion
Messages
4
Reaction score
0
Member advised to use the homework template for posts in the homework sections of PF.
If I know the angular size of the object in arcsecs let's say r, how can I convert it into steradians size? is it just that the size in steradians is r2?
 
Physics news on Phys.org
You don't, not unless you know the shape of the object. An arcsecond is an angle and a steradian is a solid angle, they are different things. It is like asking how to convert a length into an area.
 
Orodruin said:
You don't, not unless you know the shape of the object. An arcsecond is an angle and a steradian is a solid angle, they are different things. It is like asking how to convert a length into an area.

I know its spherical object (I should have mentioned it in my first post)..
Yeah, converting is not a good word for what I want to do.. Better question would be How can I obtain the size of the spherical object in steradians if I know the angular size in arcsecs.
 
Teenion said:
I know its spherical object (I should have mentioned it in my first post)..
Yeah, converting is not a good word for what I want to do.. Better question would be How can I obtain the size of the spherical object in steradians if I know the angular size in arcsecs.
Since you are working with arcsecs, I assume we're discussing very small angles. If the subtended angle (of a diameter) is theta and the distance from the observer is R, what, roughly, is the visible area? Divide that by R2 and you have the steradians.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

Similar threads

Back
Top