How to define the lower indexed tensor

  • Thread starter Thread starter ehrenfest
  • Start date Start date
  • Tags Tags
    Tensor
ehrenfest
Messages
2,001
Reaction score
1

Homework Statement


Can someone help me with QC 8.4?
I am unsure
how to define the lower indexed tensor here. I have worked with upper and lower indices before but the relationship between the two has always just been given to me.

Let me know if you want to help but think that the attachment is too small to read.

Homework Equations


The Attempt at a Solution

 

Attachments

  • zwiebach142.jpg
    zwiebach142.jpg
    10.1 KB · Views: 411
Last edited:
Physics news on Phys.org
I can't see the attempt yet. However, this problem is a forced march. Just multiply both sides of equation (8.51) by two copies of \eta to lower the indices.
 
I see:

\eta_{\beta \nu} \eta_{\alpha \mu} \epsilon ^{\mu \nu} = -\eta_{\alpha \mu} \eta_{\beta \nu} \epsilon ^{\nu \mu}

And then 2 Minkowski metrics is just the identity matrix.

Is my Einstein notation correct?
 
Last edited:
ehrenfest said:
And then 2 Minkowski metrics is just the identity matrix.
Instead of multiplying the metrics together, use them to lower the indices on \epsilon.
For instance
\eta_{\beta\nu}\eta_{\alpha\mu}\epsilon^{\mu\nu} = \eta_{\alpha\mu}{\epsilon^{\mu}}_{\beta}

ehrenfest said:
Is my Einstein notation correct?
Yes, but the equation you wrote is wrong. It is missing a minus sign on the r.h.s.
 
Last edited:
jimmysnyder said:
Instead of multiplying the metrics together, use them to lower the indices on \epsilon.
For instance
\eta_{\beta\nu}\eta_{\alpha\mu}\epsilon^{\mu\nu} = \eta_{\alpha\mu}{\epsilon^{\mu}}_{\alpha}


Yes, but the equation you wrote is wrong. It is missing a minus sign on the r.h.s.

I see.


jimmysnyder said:
Yes, but the equation you wrote is wrong. It is missing a minus sign on the r.h.s.

Fixed it.
 
I'm sorry Ehrenfest, my post #4 which you quoted is incorrect. I have edited it. Please use the edited post, not the one that you quoted.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top