How to Derive Equation (1.24) for Potential Due to a Dipole Layer?

[Azorspace]

Homework Statement

I wonder if anyone could explain me how to arrive at the equation (1.24). I have attached the part of the book where this appears.

Homework Equations

I have attached the part of the book where this appears.

The Attempt at a Solution

I have tried to make the second integral zero by performing the gradient and then the remaining algebra but i can't get to this, i suppose that the second integral is zero because in the expression (1.24) it doesn't appear. Using the term that has been expanded i tried to arrive at the integrand in (1.24) but i think that i have to make the second integral zero before this.

 

[gabbagabbahey]

No, you do not assume that the second integral is zero. If you are going to make assumptions like this, you need to come up with a good physical or mathematical argument for your assumption.

Instead, notice that the given Taylor approximation can be used on the second integral with \mathbf{x}\to \mathbf{x}-\mathbf{x}' and \mathbf{a}\to \mathbf{n}d :

\frac{1}{|\mathbf{x}-\mathbf{x}'+\mathbf{n}d|}=\frac{1}{|\mathbf{x}-\mathbf{x}'|}+\mathbf{n}d\cdot \mathbf{\nabla}\left(\frac{1}{|\mathbf{x}-\mathbf{x}'|}\right)+\ldots

To first order in d, the second integral will give you two terms; one of which will cancel the first integral, and the other produces the desired result as you take the limit in the definition of D(\mathbf{x}').