How to Derive Momentum Equations for Alpha Particles in Collisions?

AI Thread Summary
In the discussion on deriving momentum equations for alpha particles in collisions, the focus is on analyzing collisions between fast-moving alpha particles and gas atoms in a cloud chamber. The key equations involve resolving momentum both horizontally and vertically, leading to expressions for the velocities of the scattered particles. The conservation of momentum and energy principles are highlighted as essential for solving the problem. A suggestion is made to denote the initial speed of the alpha particle with a symbol for clarity. The application of kinetic energy formulas is emphasized as a necessary step in the analysis.
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Homework Statement


Fast moving α particles of mass m make collisions in a cloud chamber with gas atoms of mass M and negligible initial velocity. After a collision, the velocities of the scattered α particles and the recoiling gas atoms are v and V respectively, the former being inclined at an angle θ and the latter at an angle φ to the original α particle direction
show that 2vcos(θ+φ)=(1-M/m)V

Homework Equations


p=mv
cos(θ+φ)=cos(θ)cos(φ)-sin(θ)sin(φ)

The Attempt at a Solution


Resolving horizontally i got [1] ∑p = mvcos(θ)+MVcos(φ) and vertically i got [2] mvsin(θ)-MVsin(φ). i squared both equations and added them together to get m^2v^2+M^2V^2+2mvMVcos(θ+φ)=(Σp)^2. I'm not sure how to work out the initial velocity
 
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Is there anything in addition to conservation of momentum that you can use?
 
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Energy of the system?
 
GayYoda said:
Energy of the system?

Yes, conservation of energy.
 
how do i apply energy ?
 
GayYoda said:
how do i apply energy ?

First, I think it would be simpler if you used a symbol for the initial speed of the ##\alpha## particle: ##u## seems a good choice to me.

Second, you must the formula for the kinetic energy of a particle.
 
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