How to derive tan(2x) using the definition of the derivative ?

faisal-tesla
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Homework Statement


Can someone please derive tan(2x) using the definition of the derivative?


Homework Equations





The Attempt at a Solution



I've tried to expand it but I couldn't get anywhere with it

thank you,
 
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Show us your first steps. Did you use the formula

\tan(a+b) = \frac{\tan a + \tan b}{1 - \tan a\tan b}
 
yes i did, but i used the identity tan 2x = 2tanx/ (1-tan^2(x) )

after that, it got messy when i plugged in (x+h)
 
faisal-tesla said:
yes i did, but i used the identity tan 2x = 2tanx/ (1-tan^2(x) )

after that, it got messy when i plugged in (x+h)

Start with

\frac {\tan(2x + 2h)-\tan(2x)}{h}

and use the formula on the first term in the numerator.
 
I used both identities; it worked finally

thank you for your help . appreciated it.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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