How to Determine Angular Deceleration and Initial Speed of a Coasting Saw Blade?

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To determine the angular deceleration and initial speed of a coasting saw blade, the blade completes 1200 revolutions in 40 seconds after being turned off. Using the equation for angular displacement, the initial angular speed is calculated to be 60 RPM. The final velocity is zero, and the angular deceleration is derived from the relationship between initial speed, final speed, and time, yielding a value of 1.5 RPM/s. The calculations require converting the angular speed from revolutions per second to revolutions per minute for clarity. The method effectively demonstrates the principles of angular motion under constant deceleration.
Lance WIlliam
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A circular saw blade completes 1200 revolutions in 40s while coasting to a stop after being turned off. Assuming constant deceleration, what are (a) the angular deceleration and (b) the initial angular speed?

Answer in RPM/S
Method I used: Change in theta is 1200
Time: 40s
final Vel.:0
Initial Vel.:?
Alpha:? Eqn Used: (change in theta)=(1/2)(Initial vel.+final vel.)*time
looking for inital speed:
1200=(1/2)(initial vel+0)40seconds
Take the vel. found and place into eqn:
looking for alpha:
final vel. =Initial vel.+alpha*time


I ended up getting 1.5 ...
 
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Lance WIlliam said:
looking for inital speed:
1200=(1/2)(initial vel+0)40seconds
This will give you the angular speed in rev/s.
Take the vel. found and place into eqn:
looking for alpha:
final vel. =Initial vel.+alpha*time
That will give you alpha in rev/s/s, not RPM/s like they want. (Convert the speed to RPM--rev/min, instead of rev/s.)
 
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