How to determine period of sinx

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To determine the period of the sine function, the equation sin(x + p) = sin(x) is used, leading to the condition 2*cos(x + p/2)*sin(p/2) = 0. This implies that either p/2 must equal k(pi), resulting in p = 2k(pi), or sin(p/2) must equal zero. The latter condition indicates that p must be an integer multiple of 2π. The discussion emphasizes that the period of sin(x) is 2π, which can be proven without graphical representation by focusing on the condition sin(p/2) = 0. Ultimately, the conclusion is that the period of sin(x) is consistently 2π.
AAQIB IQBAL
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How to determine period of sin and cos functions?
I use:
sin(x + p) = sin(x)
=> sin(x + p) - sin(x) = 0
=> 2*cos(x+p/2)*sin(p/2) = 0
=> either p/2 = k(pi) => p = 2k(pi)
or x + p/2 = (2k+1)(pi)/2 => p = (2k+1)(pi) - 2x
NOW I DON'T KNOW HOW TO FIND THE SOLUTION WHICH SATISFIES BOTH.. THOUGH I KNOW THAT PERIOD IS 2(PI) BUT I HAVE TO PROVE IT WITHOUT GRAPH.
 
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Hi AAQIB IQBAL! :wink:
AAQIB IQBAL said:
sin(x + p) = sin(x)
=> sin(x + p) - sin(x) = 0
=> 2*cos(x+p/2)*sin(p/2) = 0

Fine until here. :smile:

Now that must be true for any x (for the same p) …

which can only happen if sin(p/2) = 0. :wink:

(in other words: you can ignore the other part)
 
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