How to determine period of sinx

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SUMMARY

The period of the sine function, sin(x), is established as 2π through the equation sin(x + p) = sin(x). By manipulating the equation to 2*cos(x + p/2)*sin(p/2) = 0, it is determined that sin(p/2) must equal 0 for the equality to hold for all x. This leads to the conclusion that p must be equal to 2kπ, confirming the periodicity of sin(x) without the use of graphical representation.

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AAQIB IQBAL
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How to determine period of sin and cos functions?
I use:
sin(x + p) = sin(x)
=> sin(x + p) - sin(x) = 0
=> 2*cos(x+p/2)*sin(p/2) = 0
=> either p/2 = k(pi) => p = 2k(pi)
or x + p/2 = (2k+1)(pi)/2 => p = (2k+1)(pi) - 2x
NOW I DON'T KNOW HOW TO FIND THE SOLUTION WHICH SATISFIES BOTH.. THOUGH I KNOW THAT PERIOD IS 2(PI) BUT I HAVE TO PROVE IT WITHOUT GRAPH.
 
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Hi AAQIB IQBAL! :wink:
AAQIB IQBAL said:
sin(x + p) = sin(x)
=> sin(x + p) - sin(x) = 0
=> 2*cos(x+p/2)*sin(p/2) = 0

Fine until here. :smile:

Now that must be true for any x (for the same p) …

which can only happen if sin(p/2) = 0. :wink:

(in other words: you can ignore the other part)
 

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