How to determine the integration constants in solving the Klein Gordon equation?

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Homework Help Overview

The discussion revolves around determining integration constants while solving the Klein-Gordon equation, specifically focusing on the scalar field $\phi(t,x)$. Participants explore various integration techniques and the implications of boundary and initial conditions on the constants involved.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss different methods of integrating the equation and question the correctness of their approaches. There is an exploration of the kernel of differential operators and how it relates to the functions involved. Some participants express confusion about the nature of functions arising from integration and the role of boundary and initial conditions in determining constants.

Discussion Status

The discussion is active, with participants providing insights and questioning each other's reasoning. Some guidance has been offered regarding the need for boundary and initial conditions to define functions and constants, but there is no explicit consensus on the correct approach to finding these constants.

Contextual Notes

Participants mention specific boundary and initial conditions they are considering, as well as the form of the solution to the Klein-Gordon equation. There is an ongoing inquiry into how to derive the constants from these conditions, particularly the value of $k$ in the solution.

Safinaz
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Homework Statement
How to solve the following wave equation for the scalar ##\phi(t,x)## :
Relevant Equations
##\partial_i \dot{\phi}=0 ##

Where ##\partial_i= \partial/\partial x##. And (.) is the derivative with respect for time ## \partial/\partial t##
I solved by

##
\int d \dot{\phi} = \int d x \to
\dot{\phi} = x+ c_1 \to \int d \phi = \int d t ( x+c_1)
\to \phi = x t + c_1 t + c_2
##

Is this way correct? To determine ##c_2## use initial condition: ##\phi(0,x)=0## that yields ##c_2=0##, but how to get ##c_1## ?
 
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The kernel of the operator \partial_x consists of all functions f for which \partial_x f = 0; this includes constants, but also includes functions which depend only on t. Therefore the most general element of this kernel is A(t). Hence \int \partial_x \dot \phi\,dx = \int 0\,dx \Rightarrow \dot\phi = A(t). Now integrate with respect to t. This time, the most general element of the kernel of \partial/\partial t is a function of x alone.
 
Safinaz said:
Homework Statement: How to solve the following wave equation for the scalar $\phi(t,x)$ :
Relevant Equations: ##\partial_i \dot{\phi}=0 ##

Where ##\partial_i= \partial/\partial x##. And (.) is the derivative with respect for time ## \partial/\partial t##

I solved by

##
\int d \dot{\phi} = \int d x \to
\dot{\phi} = x+ c_1 \to \int d \phi = \int d t ( x+c_1)
\to \phi = x t + c_1 t + c_2
##

Is this way correct? To determine ##c_2## use initial condition: ##\phi(0,x)=0## that yields ##c_2=0##, but how to get ##c_1## ?
Your function provably does not satisfy ##\partial_i\partial_t \phi = 0##. Just try to differentiate it!

(apart from what was already said)
 
pasmith said:
The kernel of the operator \partial_x consists of all functions f for which \partial_x f = 0; this includes constants, but also includes functions which depend only on t. Therefore the most general element of this kernel is A(t). Hence \int \partial_x \dot \phi\,dx = \int 0\,dx \Rightarrow \dot\phi = A(t). Now integrate with respect to t. This time, the most general element of the kernel of \partial/\partial t is a function of x alone.
You mean

##\dot{\phi} =A(t) \to \int \partial_t \phi = \int A(t) dt \to \phi = A(t) t + c ? ##
but what is A(t) ?
 
Safinaz said:
You mean

##\dot{\phi} =A(t) \to \int \partial_t \phi = \int A(t) dt \to \phi = A(t) t + c ? ##
but what is A(t) ?
First of all, you cannot integrate a general function A(t) with respect to t and obtain A(t) t. Not even in single variable calculus.

Second, you are still missing what was said. If ##\partial_t \phi = A(t)##, then ##\phi = a(t) + f(x)##, where ##a’(t) = A(t)##. The “integration constant” when integrating a partial derivative is generally a function of all of the other variables.
 
Orodruin said:
First of all, you cannot integrate a general function A(t) with respect to t and obtain A(t) t. Not even in single variable calculus.

Second, you are still missing what was said. If ##\partial_t \phi = A(t)##, then ##\phi = a(t) + f(x)##, where ##a’(t) = A(t)##. The “integration constant” when integrating a partial derivative is generally a function of all of the other variables.
Okay. But now how to get the definition of ##f(x)## and ##a(t)## ?
 
Safinaz said:
Okay. But now how to get the definition of ##f(x)## and ##a(t)## ?
Just as you need boundary or initial conditions to fix integration constants for ODEs, you will need boundary/initial conditions to fix those functions.
 
Orodruin said:
Just as you need boundary or initial conditions to fix integration constants for ODEs, you will need boundary/initial conditions to fix those functions.
Hello. Thanks so much for your answer. I was trying to find proper IC and BC to find ## \phi(t,x)## . Assuming:

##
bc={\phi[t,0]==1,(D[\phi[t,x],x]/.x->Pi)==0}
##
##
ic={\phi[0,x]==0,(D[\phi[t,x],t]/.t->0)==1}
##

Also ## \phi(t,x)## obays the Klein Gordon’s equation :
## \left( \frac{\partial^2}{\partial t^2} - \frac{\partial^2}{\partial x^2} \right) \phi = 0 ##

in which solution:
##
\phi(t,x) = ( c_1 e^{kt} + c_2 e^{-kt} ) ( c_3 e^{kx} + c_4 e^{-kx} ) …………(1)
##

To find the constants in Eq. (1) , BC leads to ##c_3 = c_4= 1/2 ## and the IC leads to to ##c_1=- c_2= 1/2 ## is that correct? But how to know ## k ## ?
 
Last edited:

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