How to Differentiate Cross Product?

AI Thread Summary
To differentiate the cross product of vectors U and B, the discussion references the equations dB/ds = -TN and dU/ds = KN, along with the relationship N = U x B. The key to deriving the equation dN/ds = TB - KU lies in applying the product rule, specifically the Leibniz rule, to the cross product. The original poster confirms they have solved the equation, indicating that the differentiation process was successful. The conversation emphasizes the importance of understanding the product rule in vector calculus.
nabi1995
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Hi all,


I have a qustion.

dB/ds= -TN, dU/ds= KN (1)
N= U x B (2)


dN/ds=TB-KU (3)

How Eq.(3) can be obtained from Eq.(1),(2)?


Have a nice day!
 
Mathematics news on Phys.org
product rule
 
just like any other product. leibniz rule.
 
Thank you,

mathwonk said:
just like any other product. leibniz rule.

I solved the equation. Thank you!
 

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