How to draw the angles to find force

  • Thread starter Thread starter princesspriya
  • Start date Start date
  • Tags Tags
    Angles Force
AI Thread Summary
The discussion focuses on understanding how to draw angles and resolve forces in a physics problem involving a block on an incline. Participants clarify the use of a coordinate plane to analyze the forces acting on the block, specifically the gravitational force components along the incline. It is emphasized that the normal force (Fn) and the downward gravitational force component (Fg) in the y-direction are equal in magnitude, as they oppose each other. The importance of correctly identifying the components of forces is highlighted, particularly in relation to the angles given in the problem. Overall, the conversation aids in building a foundational understanding of force analysis in physics.
princesspriya
Messages
89
Reaction score
0

Homework Statement


http://img150.imageshack.us/my.php?image=toottzx0.png


Homework Equations




I have the picture and everything but i just need help with the angles. Like i am a bit confused about how to draw the angles and stuff please help.

The Attempt at a Solution

 
Physics news on Phys.org
Use a coordinate plane so that the incline of your ramp, Ff, Ff and Fa are along the x-axis, and Fn is along the y-axis. Then you can figure out the components of the weight using the angle they give you (break the weight into its components along the incline and perpendicular to the incline).
 
so then would this picturehttp://img136.imageshack.us/my.php?image=toottup2.png be correct??
and to find the x component of the Fg i would have to do (cos30)mg and to find the y component i would have to do (sin30)mg?
 
Sin is opp/hyp and cos is adj/hyp, so you may want to re-check what the y and x-components are for Fg.
 
oo.. yea i messed it up so basically force normal(upward) would be (cos30)mg and force downward would be (sin30)mg? right?
also would force normal be the same as force gravity?
 
Last edited:
Downward and upward? Wouldn't that be the same vector?
 
force normal(Fn) is the force that was opposing gravity and force downward is the one labeled Fd so i dnt think they are the same vectors
 
Ah, yes I see what you mean. A problem with your diagram is that there is no applied force, the block is sliding down the ramp due to the force of the x-component of its weight.
 
i think i kind of understand it but i have a quick question. would the y component of Fg always be the same as the Fn?
 
  • #10
They are the only two forces in the y-direction of your coordinate plane and they are opposing each other.
 
  • #11
right so would they have the same magnitude?
 
  • #12
I don't see any other force in the y-direction.
 
  • #13
http://img524.imageshack.us/my.php?image=toottpw5.png

ok now do you see the 2 blue forces?? the one pointing down is the y component of the Fg and the one pointing up is Fn. i am just asking if both of those blue vectors would have the same magnitude?
 
  • #14
Well, if those two forces are the only forces in the y-direction and they're opposing each other, do you think that they are equal?
 
  • #15
yea because the block stays down it doesn't like go through the incline of go above in the air like it stays on the incline so both the forces have to be the same.
i m sryy its just my teacher doesn't teach anything he talks about his life so its basically a self study class and i want to understand the material because I know i am going to have to take a year of physics in college and i don't want to go in their knowing nothing. i want to atleast have a background layed.
 
  • #16
Good, now that you understand why they are equal you can move on.
 
  • #17
thx a lot! u saved me! lolzz
 
Back
Top