How to Find Charge Stored on Capacitors in Series?

AI Thread Summary
To find the charge stored on capacitors in series, first calculate the equivalent capacitance (C-eq) using the formula for capacitors in series, yielding C-eq = 5.0 μF for the given capacitors of 7.2 μF and 16 μF. The total voltage across the series connection is 15 V, and the charge (Q) on each capacitor can be found using the formula Q = C × V. Since the charge is the same for both capacitors in series, use Q = C-eq × V to determine the charge stored. The discussion highlights the importance of understanding that the charge remains constant across capacitors in series.
mli273
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1. Two capacitors, one 7.2 \muF the other 16 \muF, are connected in series across a 15 V battery.

Find the charge stored on 7.2 \muF capacitor.
Find the charge stored on 16 \muF capacitor.


2. C-eq =5.0\muF and V=Q/C and \epsilon=Q(1/C-eq)


3. I know that both Q values should be the same because the capacitors are in series, but I'm not sure how to go about using the formulas I have. I've tried averages of the two charges, and that didn't work. What am I missing? Thanks in advance!
 
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Nevermind, figured it out on my own.
 

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