How to find coefficients for sums of powers?

[ehrenfest]

Homework Statement

I encountered this formula in a proof:

Let S_k(n) be the sum of the first n positive integers raised to the power of k:

e.g. S_3(5) = 1^3 + 2^3+3^3+4^3+5^3

How would one show that

S_2(n) = (n^3/3) + (n^2/2) + an

and that

S_4(n) = (n^5/5) + (n^4/2) +bn^3 + cn^2 +dn

where a,b,c,d are constants.

Homework Equations

The Attempt at a Solution

 

[rocomath]

attempt? there needs to be at least some work b4 help is given.

 

[ehrenfest]

3. The Attempt at a Solution

n^5/5 is the integral of n^4 and n^3/3 is the integral of n^2
However, that is only true for the first term.

 

[durt]

When you're given a formula and asked to prove it, it's often helpful to try induction.

 

[Dick]

You are guessing e.g. for S4 that it is a fifth degree polynomial. Then do something in the spirit of induction. What is S4(k)-S4(k-1)? Once you answer that you can solve for the coefficients.

 

[ehrenfest]

S4(k)-S4(k-1) = k^4
So, I should set that equal to a(k)^5 + b(k)^4 + c(k)^3 +d(k)^2 + e(k) + f - [a(k-1)^5 + b(k-1)^4 + c(k-1)^3 +d(k-1)^2 + e(k-1) + f] ?
I am not sure how you solve that or how you would do induction on that.

 

[Dick]

Expand everything out and move everything to one side. Now you've got a polynomial that must equal zero for all values of k. So the coefficients of all powers of k must be zero.