How to find Density/ Radius of planetesimals

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The discussion focuses on calculating the radius of ice-rich planetesimals that are ten times the mass of Earth, assuming a density of 2 g/cm³. Participants suggest using the formula for mass (m = density × volume) and the volume of a sphere to derive the radius. The calculation involves converting Earth's mass into grams and applying algebraic manipulation to isolate the radius. The final formula derived indicates that the radius can be found using the cube root of the mass divided by the density and the volume formula. This approach effectively allows for the determination of the radius in comparison to Earth's size.
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The ice rich planetesimals that formed the cores of the Jovian planets were about 10 times more massive than Earth. Assuming such an ice ball has a density of 2g cm g-3, what would its radius be? How does this compare to Earth's radius.


I need Help =\
 
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What have you tried?
 
I was thinking of multiplying the Earths mass by 10 then using the fomula m=dv

and use the formula for volume of a sphere to get r? IDK
 
Sounds like a good plan.
 
okay so that would be m=dv


10 x 5.97 x 1024 Kg which is 5.97x 1025Kg

then convert from Kg to g 1kg= 1000g

5.97x 1025Kg x 1000 g= 5.97x 1028g
volume of a sphere= (4/3) pi r3

5.97x 1028g= (2g cm-3)((4/3)pir3)

im not to sure how to isolate R
 
You just need a bit of algebraic manipulation. It might help if you use the letters instead of numbers right until the end.
 
ok so it would be


m=d 4/3 pi r3

then m/ d(4/3)pi =r3 ?

then r = cubed root of that anwser?
 
Yes, that looks good.
 
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