How to Find Fourth Roots of a Complex Number?

Xeract
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Homework Statement



I need to find the real and imaginary roots of z^4 = -1.

The Attempt at a Solution



The polar coordinates of -1 are at (-1, pi), (-1, 3pi) etc so if I assume the solutions take the form z = exp[i n theta] then

n theta = pi + 2npi

This dosen't seem to give the correct roots though, what am I doing wrong? I don't want the solution, just the method so I can work it through for myself if anyone can help.

Thanks
 
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Are you familiar with the fact that:

Multiplying two complex numbers yields a complex number whose angle to the positive real axis is the sum of the factors' angles to the same axis (while the modulus/length of the complex number gained is the product of the facturs' moduli)?

Thus, the fourth roots of a complex number must have one fourth the angle that complex number may have, as measured to the positive real axis.

Remember that the number (-1) can be said to have the angles \pi,3\pi,5\pi,7\pi to the positive x-axis.
Ask yourself why these four angular representations are both necessary and sufficient to find ALL fourth roots of (-1)!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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