How to find invertible matrix and diagonal matrix

shellizle
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Homework Statement



Find an invertible matrix P and a diagonal matrix D such that D=P^(-1)AP.

A=
(−1 2 −2)
(−2 3 −2)
( 2 −2 3)

Homework Equations




The Attempt at a Solution



the eigenvalues are 1, 1, and 3
the eigenvector I've found so far is for the eigenvalue 3, which is t(1, -1, 1)
when i was attempting to find the eigenvector of 1,

i did (1*I-A)(x), and then reduced the matrix to

(1 1 -1)
(0 0 0)
(0 0 0)
and in polynomial form it would be
x+y-z=0

how am i suppose to put this in homogeneous form? x=(a, b, c)t

thanks in advance!
 
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shellizle said:

Homework Statement



Find an invertible matrix P and a diagonal matrix D such that D=P^(-1)AP.

A=
(−1 2 −2)
(−2 3 −2)
( 2 −2 3)

Homework Equations




The Attempt at a Solution



the eigenvalues are 1, 1, and 3
the eigenvector I've found so far is for the eigenvalue 3, which is t(1, -1, 1)
when i was attempting to find the eigenvector of 1,

i did (1*I-A)(x), and then reduced the matrix to

(1 1 -1)
(0 0 0)
(0 0 0)
and in polynomial form it would be
x+y-z=0

how am i suppose to put this in homogeneous form? x=(a, b, c)t

thanks in advance!
Your equation x + y + z = 0 will give you two solutions that correspond to the two eigenvectors you need for this eigenvalue.

x = - y - z
y = y
z = ...z

So (x, y, z) = y(-1, 1, 0) + z(-1, 0, 1)

y and z are parameters. For one eigenvector, choose y = 1, z = 0. For the other, choose y = 0, z = 1.
 
yeah i tried that,
our assignment is online based and it tells you immediately if its right or wrong..
however I've tried everything but nothing works!
does the order for the eigenvalues matter? (x1, x2,and x3)
does the engevectors have to be alligned in a specific way for A=PDP^-1 to be valid?
 
The order of the columns in your matrix P (and hence P-1) determine where the eigenvalues appear where in your diagonal matrix. Is that what you're asking?
 
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