How to find invertible matrix and diagonal matrix

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Homework Help Overview

The discussion revolves around finding an invertible matrix P and a diagonal matrix D such that D=P^(-1)AP for a given matrix A. The participants are exploring concepts related to eigenvalues and eigenvectors.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the eigenvalues of the matrix A, noting that they are 1, 1, and 3. There is an attempt to find the corresponding eigenvectors, particularly for the eigenvalue 1, and questions arise about expressing solutions in homogeneous form. One participant expresses frustration over the correctness of their attempts and questions the significance of the order of eigenvalues and the alignment of eigenvectors in relation to the validity of the equation A=PDP^-1.

Discussion Status

The discussion is ongoing, with participants sharing their findings and seeking clarification on the relationship between eigenvalues and eigenvectors. Some guidance has been offered regarding the formation of eigenvectors and the implications of their order in matrix P.

Contextual Notes

Participants are working within the constraints of an online assignment that provides immediate feedback on correctness, which adds pressure to their problem-solving process.

shellizle
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Homework Statement



Find an invertible matrix P and a diagonal matrix D such that D=P^(-1)AP.

A=
(−1 2 −2)
(−2 3 −2)
( 2 −2 3)

Homework Equations




The Attempt at a Solution



the eigenvalues are 1, 1, and 3
the eigenvector I've found so far is for the eigenvalue 3, which is t(1, -1, 1)
when i was attempting to find the eigenvector of 1,

i did (1*I-A)(x), and then reduced the matrix to

(1 1 -1)
(0 0 0)
(0 0 0)
and in polynomial form it would be
x+y-z=0

how am i suppose to put this in homogeneous form? x=(a, b, c)t

thanks in advance!
 
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shellizle said:

Homework Statement



Find an invertible matrix P and a diagonal matrix D such that D=P^(-1)AP.

A=
(−1 2 −2)
(−2 3 −2)
( 2 −2 3)

Homework Equations




The Attempt at a Solution



the eigenvalues are 1, 1, and 3
the eigenvector I've found so far is for the eigenvalue 3, which is t(1, -1, 1)
when i was attempting to find the eigenvector of 1,

i did (1*I-A)(x), and then reduced the matrix to

(1 1 -1)
(0 0 0)
(0 0 0)
and in polynomial form it would be
x+y-z=0

how am i suppose to put this in homogeneous form? x=(a, b, c)t

thanks in advance!
Your equation x + y + z = 0 will give you two solutions that correspond to the two eigenvectors you need for this eigenvalue.

x = - y - z
y = y
z = ...z

So (x, y, z) = y(-1, 1, 0) + z(-1, 0, 1)

y and z are parameters. For one eigenvector, choose y = 1, z = 0. For the other, choose y = 0, z = 1.
 
yeah i tried that,
our assignment is online based and it tells you immediately if its right or wrong..
however I've tried everything but nothing works!
does the order for the eigenvalues matter? (x1, x2,and x3)
does the engevectors have to be alligned in a specific way for A=PDP^-1 to be valid?
 
The order of the columns in your matrix P (and hence P-1) determine where the eigenvalues appear where in your diagonal matrix. Is that what you're asking?
 

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