- #1

garr6120

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Given the circuit in the diagram I was wondering would I be able to make i

I have the equation for my Super Mesh at i

-25+30i

The mesh i

subbing (2) into (1) gives:

-25+50i

V

subbing (4) into (3) gives: -25+50i

subbing (2) into (5).

45+50i

3i

Now I almost have one unknown. Is it possible to set i

Also, are the steps to finding the mesh currents correct for this problem?

_{b}equal to the mesh i_{3}.I have the equation for my Super Mesh at i

_{1}and i_{3}which is:-25+30i

_{3}+5V_{a}+20(i_{3}-i_{2})+10(i_{1}-i_{2})=0 (1).The mesh i

_{2}is equal to -2A (2).subbing (2) into (1) gives:

-25+50i

_{3}+5V_{a}-30i_{2}+10i_{1}=0 (3).V

_{a}=i_{1}-i_{2}(4).subbing (4) into (3) gives: -25+50i

_{3}-35i_{2}+15i_{1}=0 (5).subbing (2) into (5).

45+50i

_{3}+15i_{1}=0 (6).3i

_{b}=i_{1}-i_{3}(7).Now I almost have one unknown. Is it possible to set i

_{b}equal to i_{3}so i can isolate for i_{1}in equation 7. If i can't how would i be able to solve it.Also, are the steps to finding the mesh currents correct for this problem?