How to Find the Capacitance of an Isolated Ball-Shaped Conductor?

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To find the capacitance of an isolated ball-shaped conductor with charge q and radius Ri, a Gaussian surface is utilized between R1 and R2, where charge q is enclosed. The confusion arises when integrating from infinity to R2, questioning whether the enclosed charge should be zero. It is clarified that the charge enclosed by the Gaussian surface must be considered, even outside the capacitor. The integration should account for the distance from the center, from R2 to infinity. Understanding this concept resolves the initial confusion regarding charge enclosure.
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Homework Statement


Find the capacitance of an isolated ball-shaped conductor of charge q
of radius Ri surrounded by an adjacent concentric layer of dielectric
with permittivity E and outside radius R2.

Homework Equations


Capture.JPG

3. The Attempt at a Solution [/B]
I haven't understood the very first line. Otherwise everything else is fine.
From the first line, it says that we take a Gaussian surface between R1 and R2, and hence we have a charge q enclosed and we integrate this from R2 to R1. This is also fine. But my problem lies in the step where we take a Gaussian surface outside the capacitor and we integrate it from infinity to R2. But how is the charge enclosed q, should'nt it be zero?
 

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Shreyas Shree said:

Homework Statement


Find the capacitance of an isolated ball-shaped conductor of charge q
of radius Ri surrounded by an adjacent concentric layer of dielectric
with permittivity E and outside radius R2.

Homework Equations


View attachment 88129
3. The Attempt at a Solution [/B]
I haven't understood the very first line. Otherwise everything else is fine.
From the first line, it says that we take a Gaussian surface between R1 and R2, and hence we have a charge q enclosed and we integrate this from R2 to R1. This is also fine. But my problem lies in the step where we take a Gaussian surface outside the capacitor and we integrate it from infinity to R2. But how is the charge enclosed q, should'nt it be zero?
You integrate with respect to r, he distance from the centre, from R2 to infinity. And you need to consider the charge enclosed by the Gaussian surface of radius r.
 
aaaahhh! nice! Thank you very much
 
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