How to find the equation of a parabola.

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To find the equation of a parabola given the x-intercepts at (-4, 0) and (0, 0), a y-intercept of 7, and a vertex at (-2, 7), the standard form y = ax^2 + bx + c is required. The alternative form y = a(x - p)^2 + q can be used initially, where p is the x-coordinate of the vertex. Expanding this form leads to the standard form, revealing the coefficients a, b, and c. The discussion emphasizes the importance of recognizing how to convert between these forms to identify the parabola's equation. Understanding this conversion process is crucial for solving similar problems.
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Homework Statement


Find the equation of the parabola if you have the following information:
Xintersects: (-4;0) and (0;0)
Yint: y = 7
Vertex: (-2;7)



Homework Equations


The equation must be in the standard form:
y=ax^2 + bx + c


The Attempt at a Solution


I know how to put it into the equation y = a(x^2 - p) + q but I have no idea how to put it into the y=ax^2 + bx + c form, which is asked.


Thanks
 
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john_blah said:

Homework Statement


Find the equation of the parabola if you have the following information:
Xintersects: (-4;0) and (0;0)
Yint: y = 7
Vertex: (-2;7)



Homework Equations


The equation must be in the standard form:
y=ax^2 + bx + c


The Attempt at a Solution


I know how to put it into the equation y = a(x^2 - p) + q but I have no idea how to put it into the y=ax^2 + bx + c form, which is asked.


Thanks
I think you mean you know how to put it in the form y = a(x - p)2 + q. Why not put it in this form and then expand the right hand side so it looks like y=ax2+bx+c?
 
Alright but unfortunately I have got no idea how to do that. Could you please elaborate?
 
Expand the right hand side to give y=a(x2-2px+p2)+q. Now can you spot the value of a,b and c in y=ax2+bx+c from this above expression?
 
Oh my word I can't believe I did not see that before!

Thank you! :smile:
 
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