How to find the magnetic flux thru a bent loop with given angle

AI Thread Summary
To find the magnetic flux through a bent loop in a magnetic field, the relevant formula is Magnetic Flux = Area of effective * B * cos(theta). In this case, the magnetic field is 0.050 T and the angle is 45 degrees. The area of the square loop is initially considered as 10cm x 10cm, leading to a calculated flux of 3.535e-4 Wb. However, there is uncertainty about whether to adjust the area based on the bent shape, with a suggestion to use dimensions of 5cm for the base and 10cm for the height, resulting in a different flux calculation of 8.838e-5 Wb. Clarification is needed on how to accurately determine the effective area for the bent loop.
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Homework Statement



A 10cm x 10cm square is bent at a 90 degree angle. A uniform 0.050T magnetic field points downward at 45 degree angle. What is the magnetic flux through the loop?

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Homework Equations



Magnetic Flux= Area of eff *B ( Magnetic Field).
Magnetic Flux= A eff*B*cos(theta).


The Attempt at a Solution



Given:
B ( Magnetic Field) = 0.050 Tesla
Angle of 45 degree of the bent loop
Area = 10cm x 10cm

Magnetic Flux= A eff*B*cos(theta).

(0.10 cm * 0.10 cm) * 0.050 T * cos 45 degree = 3.535 e -4 Wb


Im not sure if that is correct. Although the problem gives us a area of 10cm x 10cm it seems to easy to just treat 10cm x 10cm as as the area of effected?

Do I need to incorporate 5cm for the base and 10 cm for the height?
If I do I have

(.5cm * .10cm)^2 * 0.050 * cos 45 degree = .0025 *0.050 * cos 45 degrees = 8.838e-5

I doubled .5cm * .10cm cause there is a left and right
 
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nm I got it
 
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