How to find the turns ratio between the primary and secondary coils.

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To find the turns ratio between the primary and secondary coils of a transformer, the voltage potential must be sufficient to create a spark across a 5.00 mm gap. The relevant equation is the turns ratio, which relates primary and secondary voltages and currents. The dielectric breakdown strength of air is crucial for determining the necessary potential for the spark to jump the gap. The discussion highlights confusion regarding the initial approach to solving the problem, emphasizing the importance of understanding the dielectric properties of air. Clarifying these concepts is essential for accurately calculating the turns ratio.
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Homework Statement



Find the turns ratio across the transformer such that a spark is given off at the points AB. The distance from point A to point B is 5.00 mm.

AB is the distance across the secondary coil.

The frequency and voltage of the primary coil is given.

Homework Equations



N_p /N_s = V_p / V_s = I_s /I_p


The Attempt at a Solution



I don't know where to start. I got it wrong. I was given the answer, but not the solution to the problem. Could I get some help on where to start?
 
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What potential must exist between points A and B in order for a spark to jump the gap?
 
gneill,

Thanks for helping. I honestly don't know what I was thinking. I knew the potential of the secondary coil had to be the dielectric constant of air multiplied by the distance AB.
 
nontradstuden said:
gneill,

Thanks for helping. I honestly don't know what I was thinking. I knew the potential of the secondary coil had to be the dielectric constant of air multiplied by the distance AB.

I think you mean the dielectric breakdown strength of air :smile:
 
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