How to integrate COMPLEX-valued functions?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 4K views
kingwinner
Messages
1,266
Reaction score
0

Homework Statement


How do we evaluate integrals of COMPLEX-valued functions (like the following)?

2
∫ exp[-(2+3i)x] dx
0

This integral is appearing in my PDE course in the topic of Fourier transform, but I have no background of how to integrate complex-valued functions. Looking back at my calculus textbook, all functions are assumed to be REAL-valued so really all theorems about integrals are not applicable in this situation...

Can I simply treat -(2+3i) as a scalar and use the exact same rules of integration from calculus? i.e. is integrating complex-valued functions exactly the same as integrating real-valued functions if we treat complex numbers as scalars?

Homework Equations


N/A

The Attempt at a Solution


N/A

Thanks for your help!
 
Physics news on Phys.org
In this case, the fact that you have an i in your equation makes no difference at all. If the integration path has complex values, then you should use more caution; however the kind of calculations you usually want to do in a complex plane are a fair bit different from the usual kind of integrals.
 
1) I think for complex-valued functions, we need to integrate the real and imaginary parts separately, so to integrate f where f is complex-valued, we use f = Re(f) + i Im(f). Now to integrate iIm(f), can the "i" be pulled out of the integral? (i.e. can we treat "i" as a constant?)


2) Can we say that for any nonzero complex a,
d
∫ eax dx
c
is equal to
ead/a - eac/a ??
(which is exactly the same as the case where a is a real number)

Do all the integration formulas for real-valued functions carry over analogously in the obvious way to the complex-valued function case?
Are there any examples in which the real-valued formulas does not hold in the complex-valued case?

Thanks!
 
For a complex a

[tex]\int dx e^{ax} = \frac{1}{a} e^{ax} = \frac{a^*}{|a|^2} e^{ax}.[/tex]

You really really do not have to care at all whether a is real or not, unless ofcourse if you're asked to prove that something holds for a complex number as well.
 
clamtrox said:
For a complex a

[tex]\int dx e^{ax} = \frac{1}{a} e^{ax} = \frac{a^*}{|a|^2} e^{ax}.[/tex]

You really really do not have to care at all whether a is real or not, unless ofcourse if you're asked to prove that something holds for a complex number as well.

So keeping in mind that the scalars/constants can now be complex numbers, all the formulas for integration of complex-valued functions are exactly the same as the fomrulas for integration of real-valued functions, am I right?
So is there really no real difference between integrating real or complex valued functions? Are there any examples in which this is not the case?