How to integrate COMPLEX-valued functions?

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Homework Help Overview

The discussion revolves around the evaluation of integrals involving complex-valued functions, specifically in the context of a Fourier transform encountered in a PDE course. The original poster expresses uncertainty about the applicability of traditional calculus theorems to complex functions and questions whether complex numbers can be treated as scalars in integration.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore whether the integration of complex-valued functions can be approached similarly to real-valued functions, questioning the treatment of the imaginary unit as a constant and the separation of real and imaginary parts during integration.

Discussion Status

Some participants suggest that the integration rules for real-valued functions may carry over to complex-valued functions, while others emphasize caution regarding the integration path in the complex plane. There is an ongoing exploration of whether any exceptions exist to the analogous application of integration formulas.

Contextual Notes

The discussion highlights the lack of explicit consensus on the treatment of complex-valued functions in integration, with participants questioning the assumptions underlying the application of traditional integration techniques.

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Homework Statement


How do we evaluate integrals of COMPLEX-valued functions (like the following)?

2
∫ exp[-(2+3i)x] dx
0

This integral is appearing in my PDE course in the topic of Fourier transform, but I have no background of how to integrate complex-valued functions. Looking back at my calculus textbook, all functions are assumed to be REAL-valued so really all theorems about integrals are not applicable in this situation...

Can I simply treat -(2+3i) as a scalar and use the exact same rules of integration from calculus? i.e. is integrating complex-valued functions exactly the same as integrating real-valued functions if we treat complex numbers as scalars?

Homework Equations


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The Attempt at a Solution


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Thanks for your help!
 
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In this case, the fact that you have an i in your equation makes no difference at all. If the integration path has complex values, then you should use more caution; however the kind of calculations you usually want to do in a complex plane are a fair bit different from the usual kind of integrals.
 
1) I think for complex-valued functions, we need to integrate the real and imaginary parts separately, so to integrate f where f is complex-valued, we use f = Re(f) + i Im(f). Now to integrate iIm(f), can the "i" be pulled out of the integral? (i.e. can we treat "i" as a constant?)


2) Can we say that for any nonzero complex a,
d
∫ eax dx
c
is equal to
ead/a - eac/a ??
(which is exactly the same as the case where a is a real number)

Do all the integration formulas for real-valued functions carry over analogously in the obvious way to the complex-valued function case?
Are there any examples in which the real-valued formulas does not hold in the complex-valued case?

Thanks!
 
For a complex a

[tex]\int dx e^{ax} = \frac{1}{a} e^{ax} = \frac{a^*}{|a|^2} e^{ax}.[/tex]

You really really do not have to care at all whether a is real or not, unless ofcourse if you're asked to prove that something holds for a complex number as well.
 
clamtrox said:
For a complex a

[tex]\int dx e^{ax} = \frac{1}{a} e^{ax} = \frac{a^*}{|a|^2} e^{ax}.[/tex]

You really really do not have to care at all whether a is real or not, unless ofcourse if you're asked to prove that something holds for a complex number as well.

So keeping in mind that the scalars/constants can now be complex numbers, all the formulas for integration of complex-valued functions are exactly the same as the fomrulas for integration of real-valued functions, am I right?
So is there really no real difference between integrating real or complex valued functions? Are there any examples in which this is not the case?
 

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