How to Integrate (Cos[x])/x Using Taylor Series Expansion

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Homework Statement


∫\frac{Cos(x)}{x} dx


Homework Equations



Taylor series expansion for Cos(x)

The Attempt at a Solution


I have used Taylor series to find the product of (1/x) * (cos[x]). After integration i get

In[x] - x^2/8 + x^4/96 + x^6/4320+...

I don't know what to do next, is that the answer, or there is a way of finding the function represented by the series above.
 
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plato2000 said:

Homework Statement


∫\frac{Cos(x)}{x} dx


Homework Equations



Taylor series expansion for Cos(x)

The Attempt at a Solution


I have used Taylor series to find the product of (1/x) * (cos[x]). After integration i get

In[x] - x^2/8 + x^4/96 + x^6/4320+...

I don't know what to do next, is that the answer, or there is a way of finding the function represented by the series above.

Up to an additive constant the integral is a non-elementary function called Ci(x). There is no finite, closed-form expression for Ci(x) that involves only elementary functions such as powers, roots, exponentials, trig functions, etc. That is provable: it is not just that nobody has been smart enough to find the formula, but, rather, that it has been rigoroursly proven that no such formula can possibly exist!
 
Thank you very much.
 
Well, you are allowed to integrate the series term by term (think about why!). That shows that the integral exists. What doesn't exist is an expression in terms of elementary funktions (i.e., polynomials and exponential functions and their inverses).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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