Integrating 2-Forms on the Unit Sphere

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Homework Statement


I want to integrate the 2-form defined on R^3\{0,0,0} over the unit sphere.
(x/r^3)dy wedge dz+(y/r^3)dz wedge dx+(z/r^3)dx wedge dy

Homework Equations


r=\sqrt{x^2+y^2+z^2}



The Attempt at a Solution

I'm thinking this is like a surface integral but I'm not really sure how to go about actually doing the calculation.
 
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First thing to do is convert the 2-form into polar form.
 
As hunt_mat said, you could just do the direct thing: parametrize the surface and integrate. He suggests polar coordinates; I'm not sure if he really meant cylindrical coordinates or spherical coordinates, though. It might be worth considering plain ordinary rectangular coordinates; the three summands are pretty much already set up as ordinary double integrals.


Normally you'd consider the generalized Stokes' theorem to integrate this. (Green's theorem?) But, alas, the origin is a problem.

So what if you put a tiny sphere around the origin, and used Stokes' theorem on the region between them? Or alternatively a huge sphere. If you can say something useful about the behavior of the integral on very small or very large spheres, this approach could work.
 
I meant spherical co-ordinates, as Hurkyl said the origin is a problem so, take a small sphere of radius epsilon and exclude that from the domain of integration and then once you have done the integration, take the limit as epsilon tends to zero.
 
Oh, and by the way, can't you simplify the integrand? :-p
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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