How to integrate this fraction function - help

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Use power rule for integration.
 
The 2 stays in the denominator.

{{1}\over{2x^{7}}} = {{x^{-7}\over{2}}}
 
1/(2x^7) = 1/2 x^-7, not 2x^-7
 
Pengwuino said:
The 2 stays in the denominator.

{{1}\over{2x^{7}}} = {{x^{-7}\over{2}}}

That clears it, thanks! :)
 
Alternatively, you may pull out any constant from the integral
such that: \int \frac {dx}{2x^7} = \frac {1}{2} \int \frac {1}{x^7} dx = \frac {1}{2} \int x^{-7} dx
it makes the integration a bit easier.
 
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