How to prove the limit of the sequence?

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Homework Statement


Assume the sequence \{ a_n \} satisfys 0 &lt; a_1 &lt; 1 and <br /> a_{n + 1} = a_n (1 - a_n )(n \ge 1),prove <br /> \mathop {\lim }\limits_{n \to \infty } {\kern 1pt} {\kern 1pt} {\kern 1pt} na_n = 1






Homework Equations





The Attempt at a Solution



a_n is a monotonicly decreasing sequence,and it is above zero,so a_n has a limit,zero.

let b_n=n*a_n then we got <br /> \frac{{b_{n + 1} }}{{n + 1}} = \frac{{b_n }}{n}(1 - \frac{{b_n }}{n}),but I don't know how to do next.
 
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I would go about showing first that a_n is always positive and decreasing. I would then ewxamine if you b_n is an increasing or decreasing sequence. After thay I might examine the following:

<br /> |b_{n}-1)|<br />

to see what I could find.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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