How to Prove the Sum of Squared Standard Normal Variables is Chi-Square?

[stattheory]

If Z1,Z2...Zn are standard normal random variable that are identically and independently distrubuted, then how can one prove that squaring and summing them will produce a Chi-
squared random variable with n degrees of freedom.

Any help on this will be greatly appreciated. I am new to this stuff and often get confused in it.

Stattheory.

 

[statdad]

Several ways. Start with one, set up

<br /> F(a) = \Pr(X^2 \le a) = \Pr(-\sqrt{a} \le X \le \sqrt{a})<br />

and show that f(a) = F&#039;(a) is the density for a central chi-square with 1 degree of freedom.

Then use the moment=generating method to show that the sum of n chi-squares has a chi-square distribution with n degrees of freedom.

Or, if you haven't seen moment-generating functions, start as above for 1, then
show that if W, Y are two independent chi-square random variables, with n_1 and n_2 degrees of freedom, the sum W + Y is chi-square with n_1 + n_2 degrees of freedom. The use induction for your case.

There are other ways, and I'm sure they will get proposed.