How to rearrange this equation?

[medougie]

How to rearrange this equation?
apparently 1/M (F-μmg)=μmg/g
goes to
μ=F/(M+m)g
but I don't see how please help
i never learned the simple maths and I am paying for it now

 

[mfb]

The first equation looks wrong - assuming this comes from physics, it has inconsistent units.
My guess: 1/M (F-μmg)=μmg/m
In that case, you can simplify the m/m on the right side, and multiply both sides with M afterwards.

I guess the second equation should be μ=F/((M+m)g)? Better: $\displaystyle \mu = \frac{F}{(M+m)g}$

 

[medougie]

yes your right i wrote that wrong it should have been 1/M (F-μmg)=μmg/m.
what do i do once i multiply both sides by M?
I have μ on both sides and I am solving for μ

 

[mfb]

I have μ on both sides and I am solving for μ

Bring both parts with μ on the same side, factor it out, and you are just one step away from the solution.

 

[CellCoree]

To rearrange an equation, you need to isolate the variable you want to solve for on one side of the equation. In this case, the variable we want to solve for is μ. The first step is to multiply both sides of the equation by g to get rid of the denominator on the right side. This gives us:

1/M (F-μmg) = μmg/g
⇒ (F-μmg) = μmg
Next, we can distribute the 1/M to the terms inside the parentheses on the left side:

F - μmg = μmg
⇒ F = μmg + μmg
⇒ F = 2μmg
Now, we can divide both sides by 2mg to isolate μ:

F/(2mg) = μ
Finally, we can rearrange the terms on the right side to get μ on its own:

μ = F/(2mg)
Since M+m = 2m, we can substitute this in for 2mg to get the final rearranged equation:

μ = F/(M+m)g