a4b3c2d1e0f
- 3
- 0
I kindly ask for assistance in derivation of the equation for instantaneous power in an electric circuit, P(t) = V(t) I(t). I want to derive it as rigorously as possible. Here's what I got:
We start with P = {\bf F} \cdot {\bf v}, where {\bf v} = \frac{d\bf r}{dt}<br />
We know that the force exerted on a test charge q is given by {\bf F} = {\bf E} q, and for voltage we know dV = - {\bf E} \cdot dx.
Inserting F in equation for power, we get P = {\bf E}q \cdot \frac{d\bf x}{dt} = {\bf E}\cdot dx \frac{q}{dt} = - dV \frac{q}{dt} .
How would I go from this, to the desired result, without taking a "quantum leap"?
Is there a better way to actually derive this mathematically impeccably?
We start with P = {\bf F} \cdot {\bf v}, where {\bf v} = \frac{d\bf r}{dt}<br />
We know that the force exerted on a test charge q is given by {\bf F} = {\bf E} q, and for voltage we know dV = - {\bf E} \cdot dx.
Inserting F in equation for power, we get P = {\bf E}q \cdot \frac{d\bf x}{dt} = {\bf E}\cdot dx \frac{q}{dt} = - dV \frac{q}{dt} .
How would I go from this, to the desired result, without taking a "quantum leap"?
Is there a better way to actually derive this mathematically impeccably?