How to Simplify a Boolean Logic Expression with Mismatched Parentheses?

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To simplify the Boolean expression (A+C+D)(A+C+'D)((A+'C+D)(A+'B), start by expanding the first part: (A+C+D)(A+C+'D). This involves applying distribution to combine terms, which can help identify common factors and redundancies. After expansion, further simplification can be achieved by applying Boolean algebra rules, such as the idempotent law and absorption law. It's important to carefully track the parentheses to avoid mismatches during the simplification process. Ultimately, the goal is to reduce the expression to its simplest form without using Karnaugh maps.
fran1942
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Hello, I can understand most boolean simplifications however I cannot grasp this one:
(A+C+D)(A+C+'D)((A+'C+D)(A+'B)

where the ' symbol represents a NOT.

Without using Karnaugh maps can someone please tell me how to go about simplifying this expression ?

Thank you kindly for any help.
 
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I see mismatched parentheses.

A good start would be to expand and simplify this expression: (A+C+D)(A+C+'D)

Show your working and see how far you can get.
 

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