How to Simplify a Complex Fraction in Algebra?

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SUMMARY

The forum discussion focuses on simplifying complex fractions in algebra, specifically the expression \(\frac{-y+x\left(-\frac{x}{y}\right)}{y^2}\cdot\frac{\frac{y}{1}}{\frac{y}{1}}\). Participants clarify that the simplification from step 4 to step 5 involves multiplying both the numerator and denominator by \(y\), leading to the expression \(\frac{-y^2-x^2}{y^3}\). A common point of confusion is the notation used, particularly regarding the denominator and the multiplication process.

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This is a calculus equation, but I'm having trouble with the algebra part of it.

http://calcchat.tdlc.com/solutionart/calc8e/02/e/se02e01045.gif

I'm confused about how they simplify from step 4 to 5. Can someone help me?
 
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\frac{-y+x\left(-\frac x y\right)}{y^2}\cdot\frac{\frac y 1}{\frac y 1}

\frac{-y^2-x^2}{y^3}
 
Last edited:
rocophysics said:
\frac{-y+x\left(-\frac x y\right)}{y^2}\cdot\frac{\frac y 1}{\frac y 1}

\frac{-y^2-x^2}{y^2}

you did a mistake in here! in the denominator.
 
sutupidmath said:
you did a mistake in here! in the denominator.
oops, I was so caught up on my latex I forgot about the denominator.
 
where does the y/w come from?
 
There is no y/w.

The point is, they multiplied the numerator and denominator by y.
 
kwikness said:
where does the y/w come from?
If you mean "y/1", they are just multiplying both numerator and denominator by y.
 
kwikness: If you were asekd to simplify

\frac{1 + \frac{4}{3}}{5}[/itex]<br /> <br /> you could do it, right? What is preventing you from understanding how to simplify the fraction you asked about?
 

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