How to Solve a Differential Equation Problem?

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[SOLVED] Differential Equation Problem

Hi, I am having a problem with a question in my Differential Equations class.

Homework Statement


Two drivers (A and B) are going to race from a standing start. Both leave at the same time and both have constant accelerations. Driver A covers the last 1/4 of the track in 3 seconds while driver B covers the last 1/3 of the track in 4 seconds. Who wins and by how much?

I already found a solution on this site at:

https://www.physicsforums.com/showthread.php?t=209021


I understand everything in his solution up until i get to this equation

\frac{1}{4}x = \sqrt{\frac{3a_ax}{2}}(3) + \frac{1}{2}a_a(9)

I do not know how to solve for a_a \ in \ term \ of \ x:<br /> a_a = 0.0039887x; \ \ \ \ 0.77379x...(5)

Can someone show me how this is done?

I was able to figure out how he solved this, I think my problem was that I was substituting a value for x, rather than just leaving it as x.

I used the quad. formula with:
a = 324
b = 252x
c = x^2

Homework Equations


The Attempt at a Solution



The solution to the answer from the book is Driver B wins by 6\sqrt{3} - 4\sqrt{6} sec which is approximately 0.594 sec
 
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Now that i figured out how he got his answer, is there another way to do this using integration? possibly using a = d^2 x / dt^2 ?
 
You use integration to derive the result that x(t)=x(0)+x'(0)*t+(1/2)*a*t^2 from the differential equation of which you speak.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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