How to Solve a Tricky Integration Using Prosthaphaeresis Formulas?

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I need help how to solve this integration:

\int_0^h sin[\beta(h-z)] \; cos(\beta\;z \; cos \theta)\; dz

I tried substitution of \;U=\beta(h-z)\; and going nowhere. \; cos(A+B)\; type of method won't work either because you can't get A and B out of this. Please help.

Thanks

Alan
 
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yungman said:
I need help how to solve this integration:

\int_0^h sin[\beta(h-z)] \; cos(\beta\;z \; cos \theta)\; dz

I tried substitution of \;U=\beta(h-z)\; and going nowhere. \; cos(A+B)\; type of method won't work either because you can't get A and B out of this. Please help.

Thanks

Alan

Use one of the prosthaphaeresis formulas:

\sin\theta\cos\phi=\frac{\sin(\theta+\phi)+\sin(\theta -\phi)}{2}
 
LCKurtz said:
Use one of the prosthaphaeresis formulas:

\sin\theta\cos\phi=\frac{\sin(\theta+\phi)+\sin(\theta -\phi)}{2}

Sorry to acknowledge so late, took me a while to work it out.

Thanks
 
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