How to solve acceleration in function of velocity

ahmdo
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Homework Statement



the acceleration of aparticle is defined by the relation a=-10v , where a is expressed in m/s2 and v in m/s knowing that at t=0 the velocity is 30 m/s
determine
(a) the distance the particle will travel before coming to rest
(b) the time required for the particle to come to rest
(c) the time required for the velocity of the particle to be reduced to 1 percent of its initial value

Homework Equations



a=dv/dx or vdv/dx

The Attempt at a Solution



hmm well I am not sure how to solve acceleration in function of velocity
 
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You know that a= dv/dt

so you have dv/dt = -10v.

Apply separation of variables. Do you know how to do this?
 


i did and i got v=30e^-10t
so the first and second questions has no answers...it can solve the 3rd one only
 


well you can't get a time as the time would be infinite, you can get the distance integrating with infinity as a limit.

I'd suggest you do the third part seeing as that will give a finite answer.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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