How to solve for vectors components

AI Thread Summary
To determine the car's displacement, the problem involves calculating the vector components of its journey. The car travels north at 48 mi/h for 10 minutes, which results in a displacement of 8 miles north. It then moves east for 5 miles at 66 mi/h, followed by a southwest movement at 36 mi/h for 6 minutes, translating to a displacement of 3.6 miles at a 45-degree angle. The total displacement is found by summing these vector components, and plotting them tail-to-head can help visualize the resultant vector. Properly accounting for angles and directions is crucial for accurate calculations.
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Homework Statement


A car drives north at 48mi/h for 10 min and then turns east and goes 5.0 mi at 66mi/h . Finally, it goes southwest at 36mi/h for 6.0 min.

Determine the car's displacement.

Assume that the positive x and y axes are directed to the east and north, respectively.
Answers should be in x and y components of the resultant

Homework Equations


x component aka i hat lies in the x-axis
y component aka j hat lies in the y axis

The Attempt at a Solution


since the car is going north at that velocity. the magnitude of that vector is 8 mi. When the car goes east, the magnitude is given as 5.0mi. when the car moves southwest, the magnitude is 3.6mi.

Not sure if the graph is right but I thought I get feedback on it.

vector_zps56d5285d.png
 
Last edited:
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The total displacement is merely the sum of the given vectors. Write each vector in terms of its components. Note that a direction like southwest implies a 45 degree angle between south and west, this should help you write the components.

To find a vector component in a direction, you need to know the angle between the vector and that direction.
 
since the car is going north at that velocity. the magnitude of that vector is 8 mi. When the car goes east, the magnitude is given as 5.0mi. when the car moves southwest, the magnitude is 3.6mi.

correct...

so plot these on graph paper, tail to head [ector arrow point], and connect the final head to the origin...the length is your final magntiude and the angle you measure relative to horizontal records the orientation. ..so for example, go 8 up [vertical], from there 5 down and to the right at 45 degrees 5, then horizontal right from there 3.6...
 
I thought it was 5 horizontal right and 3.6 down left. Thanks for the feedback. i added a picture on what I did with the vector components. I feel super stuck on this problem.
 
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