How to Solve the Equation X^2 + 1 = 0 (mod 5^3)?

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SUMMARY

The equation x^2 + 1 = 0 (mod 125) has been analyzed, revealing that it can be reduced to x^2 + 1 = 0 (mod 5). The solutions for the latter are x = 4 and x = -4, indicating two distinct solutions. The derivatives at these roots, f '(4) and f '(-4), are not congruent to 0 (mod 5), confirming that these roots are nonsingular. This analysis establishes the foundational understanding of solving quadratic equations in modular arithmetic.

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brute26
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How would i start to solve this problem?

x^2 + 1 == 0 (mod 5^3).

Find all solutions.

How do i know how many solutions there are? If i reduce it to
x^2 + 1 == 0 (mod 5), i get that x= 2,3,7,8,12, etc.
 
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ok, so now i know that it has 2 solutions, because x^2 + 1 == 0 (mod 5) has only two solutions, namely x= 4, x= -4.

however f '(4) and f '(-4) are not congruent to 0 (mod 5). So these roots are nonsingular?
 

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