How to solve the ODE ty' + 2y = 4t^2

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Homework Statement


Hi all, I'm trying to solve an ordinary differential equation. The problem is ty' + 2y = 4t^2


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The Attempt at a Solution



I got down to \int (t^{2})\frac{dy}{dt} + \int 2ty = \int 4t^{3}

I am not sure about how to integrate the left side of the equation. The dy/dt make y make the problem confusing.

 
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just recognize
t^2 y' + 2 t y = (t^2 y)'
and use the fundamental theorem to say
\int f'(t) dt = f + C.
 
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