How to solve this integration problem problem did but got wrong answer

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Homework Statement


Find the volume generated by rotating the region bound by the given curves about the x axis



Homework Equations


x=1+(y-2)^2, x=2

The Attempt at a Solution



i solved the problem using cylinder shells method. the solution equation i got was
integration of 2phiy(1+y^2-2y+4)dy. the upper limit of the equation i got was 3 and the lower limit was 1.
the answer i got was 142.42 but it came out to be wrong.
can anyone help me.
 
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The length of your shell should be 2-(1+(y-2)^2), right? When I expand that, I don't get (1+y^2-2y+4). Can you check that part?
 
thank you i got it now...what i did in my solution was that i didnt subtracted x=2 from the equation x= 1+ (y-2)^2.
thanks for the help.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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