How to solve this ratio/proportionality question?

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The discussion focuses on calculating the gravitational pull of the Moon on Earth's oceans compared to that of the Earth itself. The gravitational pull of the Moon is determined to be approximately 3.40 x 10^-5 N/kg, while the Earth's pull is 9.8 N/kg. To find the ratio, one can divide the Moon's gravitational pull by the Earth's, resulting in a value of about 3 millionths. The participant expresses difficulty with understanding ratios and proportionality in physics, but ultimately receives guidance on the calculation process. The conversation concludes with the realization that the calculation was simpler than initially thought.
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The Moon's gravitational pull on the Earth causes the ocean tides. Show that the gravitational pull of the Moon on the Earth's oceans is approximately 3 millionths of the gravitational pull of the Earth on its oceans. Assume that the distance from the Earth to the Moon is 380,000 km.
Other given/worked out previously: mass of moon = 7.35 x10^22kg, surface gravitational field strength of the moon: 1.62Nkg^-1, radius of the moon = 1740km (3sf)

g at the Earth's surface is 9.8.
g at moon's surface I worked out using the formula g = GM/r^2,g * mass of moon/ distance from moon to Earth sqred = 3.40x10^-5 (3sf)

My big problem is the ratios. How do I show that its 3/1000000 of the grav. pull of the Earth? I know that grav pull of the Earth on oceans will be 9.8 and the moon on the ocean will be 3.40x10^-5, but I just simply do not know how to do physics ratio questions whatsoever. I am terrible at them... How do I approach ratio/ proportionality question such as this one? What is the process?
 
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Tangeton said:
The Moon's gravitational pull on the Earth causes the ocean tides. Show that the gravitational pull of the Moon on the Earth's oceans is approximately 3 millionths of the gravitational pull of the Earth on its oceans. Assume that the distance from the Earth to the Moon is 380,000 km.
Other given/worked out previously: mass of moon = 7.35 x10^22kg, surface gravitational field strength of the moon: 1.62Nkg^-1, radius of the moon = 1740km (3sf)

g at the Earth's surface is 9.8.
g at moon's surface I worked out using the formula g = GM/r^2,g * mass of moon/ distance from moon to Earth sqred = 3.40x10^-5 (3sf)

My big problem is the ratios. How do I show that its 3/1000000 of the grav. pull of the Earth? I know that grav pull of the Earth on oceans will be 9.8 and the moon on the ocean will be 3.40x10^-5, but I just simply do not know how to do physics ratio questions whatsoever. I am terrible at them... How do I approach ratio/ proportionality question such as this one? What is the process?
You're nearly there, what do you get if you divide the moon's pull on the ocean, by the Earth's?
 
Vagn said:
You're nearly there, what do you get if you divide the moon's pull on the ocean, by the Earth's?
Okay that was too easy. Thanks.
 
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