How to write 100 and -100 in phasor notaion

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In phasor notation, a constant voltage of 100V can be represented as 100V ∠ 0°, while -100V can be expressed as 100V ∠ 180°. It's important to clarify that these representations are valid for AC voltages with specified phase shifts. If the values of 100 and -100 are peak values, they should be converted to RMS values, resulting in a factor of √2 adjustment. Phasors are only applicable for steady-state sinusoidal signals, and for DC voltages, phasors do not apply.
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1. Write the following signals in phasor notation: v7(t)=100, v8(t)=-100(



2. Acos(wt + Θ) = Ae^(j Θ)



3. I want to say 0 because its just a constant, if not then 1 because Θ=0. It seems to easy. Is it 0?
 
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If it's an AC voltage with 0° phase shift, then the 100V source is just 100V ∠ 0°. The -100V source can be written as -100V, or alternatively, 100V ∠180°. Often, when the angle is 0 or 180 the shorthand 100V or -100V is adequate, so long as you make sure to specify clearly that it's a phasor value.

EDIT: As rude man points out in his (the next) post, phasor magnitudes are generally taken to be RMS values. If your given values of 100 and -100 are peak values of the sinusoid, then convert to RMS.
 
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If a voltage in the time domain is v(t) = v0 sin(wt + θ) then the phasor is
V = (v0/√2)e.

So your equation 2 is off by a factor √2 and in 3 if the voltages are dc then there is no phasor at all since there is no sinusoidal voltage.

Phasors are applicable only for steady-state sinusoids.

If v7 = 100 sin(wt) or -100sin(wt) then the above should provide you your answers.
 

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