How would I find the half-reactions?

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In the discussion about the redox reaction 2MoS2 + 7O2 → 2MoO3 + 4SO2, the focus is on identifying the oxidation and reduction processes. The reaction is already balanced, but the user seeks clarity on the half-reactions involved. It is noted that two species are oxidized while one is reduced, with a suggestion to assign oxidation numbers to clarify which elements are undergoing these changes. Resources such as Khan Academy and a previous forum thread are recommended for further understanding of oxidation states and the half-reaction method. The complexity of polysulfides is acknowledged, with a specific mention of the oxidation number for sulfur in certain forms, indicating that sulfur can have variable oxidation states.
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2MoS_{2} + 7O_{2} \rightarrow 2MoO_{3} + 4SO_{2}

So here I have a redox reaction, it's already balanced but just for kicks I'm trying to find the half-reactions so that I know what is happening. I'm having some trouble though as I don't know what's being oxidized and what's being reduced. Any advice?

Thanks!

BiP
 
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Two things are oxidized and one is being reduced.

The one that is being reduced should be obvious.
 
Sorry I don't catch it still. Which one is being oxidized and how do you know?

BiP
 
Did you try assigning oxidation numbers?

If you're not sure about how to do that, this should help:
http://chemistry.about.com/od/generalchemistry/a/oxidationno.htm

Also, khanacademy.org has some excellent videos (I think three in total) about redox reactions and oxidation states. Start with this one: http://www.khanacademy.org/video/introduction-to-oxidation-states?topic=chemistry and work your way through the next few.

I also recently asked a question about balancing by half-reaction method here, and got some good help which may in turn help you: https://www.physicsforums.com/showthread.php?t=578120
 
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The problem is both Molybdenum and Sulphur have variable oxidation numbers so I don't know what they are.

BiP
 
Polysulfides are a little bit tricky. In general they have a form Sn2-. For S22- you can safely assume both sulfur atoms are identical and each has an oxidation number of -1. This is analogous to hydrogen peroxide where both oxygen atoms are assigned ON of -1.
 
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