How would you compartmentalize this circuit?

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The discussion revolves around the compartmentalization of a complex op-amp circuit into stages, specifically focusing on a two-stage inverting configuration. Participants explore how to handle feedback, particularly from resistors R3 and R6, and how it affects the overall gain of the circuit. They emphasize the importance of applying Kirchhoff's Laws to analyze the circuit, noting that while the stages can be treated separately, feedback creates dependencies that complicate isolation. The circuit's behavior under varying resistor values is examined, with some suggesting it resembles a Schmitt trigger due to its feedback characteristics. Ultimately, the conversation highlights the circuit's complexity and the need for careful analysis to understand its transfer function and gain.
  • #31
I did some playing around with the numbers tonight and I cannot make the gain of this circuit -3 with the original resistance values that I picked which were: R1, and R5 1 ohm and all the rest 2 ohms. I wrote up something quick on the computer which could take this through as many iterations as I wanted until all the voltages settled down or the circuit settled into a steady increase towards infinity. Bottom line seems to be that if R3 is sufficiently large R6 can offset the positive feedback if R6 is sufficiently small. But what is the most interesting is that if R6 and R1 are sized such that the input is canceled in the second stage and R5/R4 = R2/R3 whatever voltage that is on the outputs will stay that way. Jim, you said that
if R5/R6 = R2/R1 gain is zero
which is correct in that the signal never gets into the second stage. You also said
R5/R4 = R2/R3 makes gain approach infinite
Well, not quite. Both of those conditions can be met at the same time. If you set these resistances up this way in a world with perfect opamps and perfect resistors we could give a resistor a slight momentary tweak in resistance and the voltages would drift in the appropriate direction and at the moment the resistance goes back to satisfy R5/R4 = R2/R3 whatever voltage that is on the outputs will stay this way indefinitely. Of course in the real world there are offset errors and tolerances so eventually it would drift.
 
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  • #32
Averagesupernova said:
Well, not quite. Both of those conditions can be met at the same time.
Sure, if both are met gain is 0/0 , indeterminate
the circuit is on a cusp ready to tumble into one of two states ?
 

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