Hw help with vector natur of Newton's second law of motion

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To solve for the acceleration of the object with a mass of 3.00 kg under the influence of two forces (40.0 N east and 60.0 N at 45 degrees north of east), first break the second force into its components using trigonometric functions: F_x = F*cos(θ) and F_y = F*sin(θ). The x-component of the second force is 60.0 N * cos(45°), and the y-component is 60.0 N * sin(45°). After calculating the components, sum the forces in both the east and north directions to find the resultant force. Finally, use Newton's second law (F = ma) to determine the magnitude and direction of the acceleration relative to the x-axis.
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only two forces act on an object (mass = 3.00 kg). 40.0N east and 60.0N north of east at 45 degrees. Find the magnitude and the direction (relative to the x axis) of the acceleration of the object.

I don't really know where to begin.
 
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Add the components of the two vectors to make a sum vector. Add the two components in the N direction to get the N sum, and add the two components in the E direction to get the E sum. How do you break up the 2nd vector into its N and E components? All you need is a little trig.
 
Use the relationships: F_{x} = F\cos\theta, F_{y} = F\sin\theta
 
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