HW Question, very simple. mass/gravity

  • Thread starter Thread starter ek378996
  • Start date Start date
AI Thread Summary
If a planet is half the size of Earth but has the same gravitational pull, its mass must be four times greater than that of Earth. This conclusion stems from the relationship between mass, radius, and gravity, where the gravitational force is proportional to mass and inversely proportional to the square of the radius. Therefore, if the radius is halved, the mass must increase by a factor of four to maintain the same gravitational acceleration. The discussion clarifies the mathematical relationship underlying these concepts. Understanding this relationship is crucial for grasping how mass and gravity interact in planetary bodies.
ek378996
Messages
2
Reaction score
0
If a planet is 1/2 of earth, gravitational is the same of earth, what does that tell you about the mass?
 
Physics news on Phys.org
ek378996 said:
If a planet is 1/2 of earth

half the size?

anyhow...What is mass affected by?
 
yes, half the size. Nothing, just trying to find out if the mass of the planets is 2 or 4 times larger/smaller than earth.

basically if a planet is half the size of the earth, and gravitation is the same as earth, what would the planets mass have to be? 2 or 4 times larger than earth?
 
Last edited:
Greetings:

If acceleration due to gravity is equal for both the Earth and another planet, then,

Gme / re2 = Gmp / rp2.
==> me = (re / rp)2 mp
==> me = (2rp / rp)2 (given re = 2rp)
==> me = 4mp

Regards,

Rich B.
rmath4u2@aol.com
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top