Hydraulic head as a function of flow rate

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SUMMARY

The discussion focuses on calculating hydraulic head as a function of flow rate in a piping system containing water at 20°C. Key variables include flow rate (##\dot{V}##), hydraulic head (##H##), gravitational acceleration (##g = 9.81 \frac{N}{kg}##), atmospheric pressure (##P_{atmosphere} = 101325Pa##), and water density (##\rho = 1000\frac{kg}{m^3}##). The user seeks to determine the hydraulic head at zero flow and the maximum flow rate (##QMax##) where the hydraulic head is three times that at zero flow. The relevant equations include $$H = \frac{P_{In} - P_{atmosphere}}{g\rho}$$ and $$H_1 - H_2 = R\dot{V}$$.

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Ronanvdv
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Hello!
1. Homework Statement
Symbols and variables:

##\dot{V}## : flow rate
##H## : Hydraulic head
##g = 9.81 \frac{N}{kg}##
##P_{atmosphere} = 101325Pa##
##\rho = 1000\frac{kg}{m^3}##
I am given a piping system, with serie and parallel pipes, they start from one point and go back into one point.

I need to plot the hydraulic head (the medium in the piping system is water at 20°C, and the local flow loses are negligible) in function of the flow rate, for ##H(\dot{V}=0 \frac{m^3}{s})## to ##H(QMax)##.
With ##QMax## the flow rate where the hydraulic head is 3 times the hydraulic head by zero flow.

The question:
  1. How can I calculate the hydraulic head by zero flow
  2. How can I calculate the maximal flow rate
My instruction paper is in dutch (reason why i didn't upload it)

Homework Equations


In my instruction paper:
$$H = \frac{P_{In} - P_{atmosphere}}{g\rho}$$
Further the mechanical equation out of my syllabi:
$$H_1 - H_2 = R\dot{V}$$

The Attempt at a Solution


In appendix.
I also includes a plot from what I think the solution is. (hydraulic head in function of flow rate)

But what i don't understand, how can (according to my solution) the hydraulic head be negative.
Does someone know how or knows a resource.

Thanks in advance,
Good day!
 

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Is there a diagram?
 
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