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How much Na2B4O7 * 10H2O and 20% hydrochloric acid solution is needed to make 31 g boric acid?

My work:

[tex]\frac{x}{Na_2B_4O_7 * 10 H_2O} = \frac {31}{4 H_3BO_3}[/tex]

x = 47.8 g

[tex]\frac {0.2x}{3HCl} = \frac {31}{4 H_3BO_3}[/tex]

x = 275 g

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# Hydrochloric acid solution is needed to make 31 g boric acid?

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