Interpreting Hydrogen Atom Wave Functions: A Question of Correctness?

In summary, you solved the equation for the e branch, but you don't know where to start with the other branches.
  • #1
gfxroad
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0

Homework Statement



I solved the Schrödinger equation, obtaining a wave function in terms of Radial and the spherical harmonics as follows:

$$Ψ(r,0)= AR_{10} Y_{00} + \sqrt{\frac23} R_{21} Y_{10} + \sqrt{\frac23} R_{21} Y_{11} - \sqrt{\frac23} R_{21} Y_{1,-1}$$


Homework Equations




The Attempt at a Solution


The constant A is equal to i; is this result right or not?
 
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  • #2
Please provide a problem statement.
But I doubt the constant is going to be imaginary - what is your reasoning?
 
  • #3
The states is more to write but I make a print screen.

http://www.gfxroad.com/print-wf
 
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  • #4
I can see why you didn;t want to write that down ;)
See the line below the equation where it says "where A is a real constant..."?
Your question:
The constant A is equal to i; is this result right or not?
... is answered.

You seem to be trying to answer part (b).
What is the condition that must be satisfied for ##\psi(\vec r,0)## to be normalized?
 
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  • #5
∫ψψ*dτ=1
 
  • #6
Very good ... imagine you had ##\psi = a\psi_a + b\psi_b## ... where ##\psi_a## and ##\psi_b## are already normalized. In order for ##\psi## to be normalized, ##a## and ##b## need to satisfy a condition ... what is it?
 
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  • #7
a2+b2=1
 
  • #8
Well done.
Technically: ##a^*a+b^*b=1## in case you have complex coefficients.

Now imagine you have:

##\qquad \psi = a\psi_a + \sqrt{\frac{2}{3}}\psi_b + \sqrt{\frac{2}{3}}\psi_c - \sqrt{\frac{2}{3}}\psi_d##

... now your problem is that to get ##|\psi|^2=1## it looks like you have ##a^2+2=1 \implies a=\sqrt{-1}##

But you are told that ##a## is real so this is a contradiction.
Anyway, if ##a=i##, then ##a^*a= (-i)i = -i^2=1## not the -1 you were looking for.

In fact, is there even a solution for ##a^*a=-1##?

Therefore - what does this tell you about your approach?
Did you properly account for the R and Y functions?
i.e. is ##\psi_{nlm}=R_{nl}Y_{lm}## normalized already?
... did you do part (a) correctly?
 
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  • #9


Yes, I thought part a was done correctly like:
http://www.gfxroad.com/print2
 
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  • #10
Yeah, I'm getting the same thing ... I have a nagging feeling there's a wrinkle here I'm missing but on the face of it the textbook problem has no solution.

It may be that the text-book has a typo.
 
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  • #11
What's about e branch, is there any starting point or equation for this, because I don't know where can I starting. The other branches solved correctly.
 
  • #12
For (e) ##\text H\psi_{nlm}=E_n\psi_{nlm}##

What do you mean "correctly"? Do you have model answers?
 

1. What is a hydrogen atom wave function?

A hydrogen atom wave function is a mathematical description of the probability of finding an electron in a certain location around the nucleus of a hydrogen atom.

2. How is a hydrogen atom wave function represented?

A hydrogen atom wave function is typically represented by the Greek letter psi (Ψ) and is a function of the position coordinates of the electron.

3. What information does a hydrogen atom wave function provide?

A hydrogen atom wave function provides information about the energy levels and orbital shapes of the electron in a hydrogen atom.

4. How are hydrogen atom wave functions used in chemistry?

Hydrogen atom wave functions are used in chemistry to predict the electron density and behavior of atoms, as well as to understand chemical bonding and reactions.

5. Can hydrogen atom wave functions be observed?

No, hydrogen atom wave functions cannot be directly observed. They are a theoretical concept used to describe the behavior of electrons in a hydrogen atom.

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