Hydrostatic stress on cube placed in deep sea

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SUMMARY

In a hydrostatic condition, a metal cube placed in the deep sea experiences no shear stress on any of its faces. This is due to the isotropic nature of the stress tensor, which results in equal normal stress on all sides and zero shear stress. Consequently, no Mohr circle can be drawn, as shear stress does not exist in any orientation. This principle applies equally to both two-dimensional and three-dimensional stress scenarios.

PREREQUISITES
  • Understanding of hydrostatic stress conditions
  • Knowledge of stress tensors and their isotropic properties
  • Familiarity with Mohr's circle for stress analysis
  • Basic principles of mechanics of materials
NEXT STEPS
  • Study the properties of isotropic materials in stress analysis
  • Learn about hydrostatic pressure effects on solid objects
  • Explore advanced applications of Mohr's circle in three-dimensional stress analysis
  • Investigate the implications of shear stress in various engineering materials
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Ravi Singh choudhary
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Ques: If one metal cube placed in deep sea where will be maximum shear stress in cube?

What I know: In hydrostatic condition there would be no shear stress, that means on any face of cube there would be not shear stress at all.
In case of two dimensional stress; if we have same normal stress on the sides and zero shear stress we cannot draw Mohr circle; that means we cannot have shear stress in any orientation.

My doubt: Whether it would same for three dimensional cube as in 2D case.
 
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Ravi Singh choudhary said:
Ques: If one metal cube placed in deep sea where will be maximum shear stress in cube?

What I know: In hydrostatic condition there would be no shear stress, that means on any face of cube there would be not shear stress at all.
In case of two dimensional stress; if we have same normal stress on the sides and zero shear stress we cannot draw Mohr circle; that means we cannot have shear stress in any orientation.

My doubt: Whether it would same for three dimensional cube as in 2D case.
Hi Ravi, Is this question for schoolwork?
 
Ravi Singh choudhary said:
Ques: If one metal cube placed in deep sea where will be maximum shear stress in cube?

What I know: In hydrostatic condition there would be no shear stress, that means on any face of cube there would be not shear stress at all.
In case of two dimensional stress; if we have same normal stress on the sides and zero shear stress we cannot draw Mohr circle; that means we cannot have shear stress in any orientation.

My doubt: Whether it would same for three dimensional cube as in 2D case.
It's the same for 3D. The stress tensor will be isotropic, and the stress vector on an arbitrary plane of any orientation through the cube will be normal to the plane. There will be no shear stress.
 
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berkeman said:
Hi Ravi, Is this question for schoolwork?
No this was once asked in BARC interview for mechanical engineers
 
Chestermiller said:
It's the same for 3D. The stress tensor will be isotropic, and the stress vector on an arbitrary plane of any orientation through the cube will be normal to the plane. There will be no shear stress.
Thanks sir.
 

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