Hyperbola: define epicenter word problem

AI Thread Summary
The discussion revolves around solving a word problem related to hyperbolas and earthquake wave detection. The problem involves three stations, with Station A detecting P-waves first, followed by Station B and Station C at different intervals. The key confusion is about the distance between Stations A and B, where the poster initially misinterprets the wave travel distance as 12 kilometers instead of recognizing that the epicenter's location is determined by the difference in wave arrival times. The poster concludes that the epicenter is closer to Station A, based on the hyperbolic equations derived from the stations' coordinates and the time differences. The final solution suggests that the epicenter lies in the fourth quadrant, closer to Station A, at the intersection of the hyperbolas formed by the stations.
ducmod
Messages
86
Reaction score
0

Homework Statement


Hello!
Here is the word problem that should be solved based on hyperbola equation (exercise from
hyporbola topic):
The P-waves (\P" stands for Primary) of an earthquake
in Sasquatchia travel at 6 kilometers per second.10 Station A records the waves rst. Then
Station B, which is 100 kilometers due north of Station A, records the waves 2 seconds later.
Station C, which is 150 kilometers due west of Station A records the waves 3 seconds after
that (a total of 5 seconds after Station A). Where is the epicenter?

My question is about the first part, i.e. station A and B (for now):

Given the distance between station A and station B of 100 km,
and the speed of waves of 6 km/second, and the fact that
station A has recorded the wave 2 seconds earlier than station B,
how can the distance between them be 100 km?

Please, help me to understand this and correct me:
wave speed is 6 km/sec, hence in 2 seconds it covered 12 kilometers.
Shouldn't it mean that the distance between A and B is 12 km, which is
the same as to say that the epicenter is 12 kilometers closer to A than
to B?Thank you!

Homework Equations

The Attempt at a Solution

 
Physics news on Phys.org
ducmod said:

Homework Statement


Hello!
Here is the word problem that should be solved based on hyperbola equation (exercise from
hyporbola topic):
The P-waves (\P" stands for Primary) of an earthquake
in Sasquatchia travel at 6 kilometers per second.10 Station A records the waves rst. Then
Station B, which is 100 kilometers due north of Station A, records the waves 2 seconds later.
Station C, which is 150 kilometers due west of Station A records the waves 3 seconds after
that (a total of 5 seconds after Station A). Where is the epicenter?

My question is about the first part, i.e. station A and B (for now):

Given the distance between station A and station B of 100 km,
and the speed of waves of 6 km/second, and the fact that
station A has recorded the wave 2 seconds earlier than station B,
how can the distance between them be 100 km?

Please, help me to understand this and correct me:
wave speed is 6 km/sec, hence in 2 seconds it covered 12 kilometers.
Shouldn't it mean that the distance between A and B is 12 km, which is
the same as to say that the epicenter is 12 kilometers closer to A than
to B?Thank you!

Homework Equations

The Attempt at a Solution

The primary wave travels from the hypocenter to A, from the hypocenter to B, from the hypocenter to C, not from A to B.
ducmod said:
Shouldn't it mean that the distance between A and B is 12 km, which is the same as to say that the epicenter is 12 kilometers closer to A than to B?
These two statements are not the same.
 
Last edited:
I think I got it. Please, take a look at my results and let me know if they are correct, and if not, please, guide me to find my mistakes:

1) station B is located due north from station A and both are at the foci; distance between them is 100 km.
Assume the center of hyperbola is at (0, 0), hence the equation is y^2 / b^2 - x^2 / a^2 = 1.
c = 50, coordinate of station A is (0, -50), B (0, 50)
b = 6 (half of the difference in the distance that the sound had to travel to B, i.e. 2 seconds * 6 km/sec = 12, half of it is 6)
(it is a vertical hyperbola, hence it's be, not a, that is equal to 6).
a^2 = c^2 - b^2 = 2464
thus equation for this *vertical* hyperbola between A and B stations is y^2 / 36 - x^2 / 2624 = 1

2) station C is 150 due west from station A, hence it lies at (-150, -50),
The hyperbola between station C and A is a horizontal one, and given the difference in wave detection
of 3 seconds, a = 9.
c = 75. center at (-75, -50)
b^2 = c^2 - a^2 = 5544
equation (x + 75)^2 / 81 - (y + 50)^2 / 5544 = 1

The epicenter lies closer to A in both cases, hence the point will be in the 4th quadrant, closer to A,
at the intersection of lower part of A-B hyperbola and right part of A-C hyperbola.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top