I am having trouble relating to impulse

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The discussion revolves around calculating the impulse delivered by a super ball when it strikes a wall and the average force during the collision. The ball has a mass of 4.0g and strikes at a speed of 15.0 m/s, with a subsequent movement of 0.50 cm towards and away from the wall. Participants are working through the equations of momentum and impulse, with some confusion regarding the mass conversion and average speed during the collision. The average speed is critical for determining the total time of the collision, and kinematic equations are applied to solve the problem. Overall, the thread highlights the challenges in relating impulse and average speed in collision scenarios.
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1. A super ball, made of rubblerlike plastic, is thrown against a hard smooth wall. The ball has a mass of 4.0g and strikes the wall from a perpendicular direction with a speed of 15.0 m/s. For simplicity, assume that the acceleration is constant while the ball is in contact with the wall. After touching the wall, the center of mass of the Super Ball moves .50 CM toward the wall and then moves the same distance away to the complete the bounce.
What is the magnitude of the impulse delivered by the wall?
What is the magnitude of the time average force?

2. dMomentum= MV'-MV, Impulse=(MV'-MV)/dt
3. Pretty lost here. I tried relating the movement of the center of mass to the dt and then treating dmomentum. So [(-15m/s)(0.004kg)-(15m/s)(0.004gk)]=-0.12 N.S then
1.2N/S/(0.005m/15m/s)
 
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harvellt said:
So [(-15m/s)(0.04kg)-(15m/s)(0.04gk)]=1.2 N.S
The mass is 0.004 kg, not 0.04.
then
1.2N/S/(0.005m/15m/s)
What's the average speed during the collision? Use that to find the total time of the collision.
 
Well the conversion is a little embarrassing but where I am lost is finding the average speed over the collision.
 
Assume the acceleration over each half of the collision is uniform. The initial speed is V0 and the final speed is 0. So what's the average speed?
 
Thank you so much I used the kinematics dx=1/2(dv)t, and got it.
 
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