Well, I took it alright. There were two problems that I think I messed up something on, but overall, I think I probably scored around a 90. He's good about posting grades the next day if not the same night, so I'll know real soon.
The one that I just couldn't figure out asked me to list the first 4 terms in a Maclaurin Series representation of a function, and then use the Series as a whole to estimate an definite integral.
I believe it was:
\int_{0}^{\frac{1}{2}}cos(x^{2})dx
So, I recalled that:
\sum_{n=0}^{\infty}\frac{(-1)^{n}x^{2n}}{(2n)!} = cos(x)
and so, the representation was:
\sum_{n=0}^{\infty}\frac{(-1)^{n}x^{4n}}{(2n)!} = cos(x)
I used that Series, to list out the first 4 terms (for n:0,1,2,3).
I then put that series in place of the above integral, and the result was some series with 4n+1 and (2n!) in the denominator, that I couldn't quite manipulate to make it look like a known series. I was thinking it would come out to be geometric, well, sort of, it was alternating, so I tried using the alternating series test, but I couldn't figure out how to estimate it's value considering there was no error given to me. I know that:
|e| = |S-S_{n}| <= b_{n+1}
but again, no given error?
After that, they wanted me to find the 8th derivative of cos(x^2) evaluated at zero. There were 2 homework problems we did along time ago like this, but it wasn't coming back to me, this whole problem was a nightmare. I tried setting my series for cos(x^2) equal to the definition of the maclaurin series:
\sum_{n=0}^{\infty}\frac{(-1)^{n}x^{4n}}{(2n)!} = \sum_{n=0}^{\infty}\frac{f^{(8)}(0)x^{8}}{8!}
and then I set 4n = 8, to find the n for the left side (n=2). I put all n's on the left to 2, and did the math to solve for f^(8)(0) but I got some insane number in the hundreds that just did not seem right. So who knows...
Only my physics final to go!